MATH SOLVE

3 months ago

Q:
# URGENTThe point (0, -9) is the focus of the parabola shown What is the equation of the parabola? y=1/36x^2 y=1/9x^2 y=-1/36x^2 y=-1/9x^2

Accepted Solution

A:

The function of the parabola can be expressed as :

(x - h)^2 = 4p (y - k)

Where the coordinate of the focus is (h + p, k) , the vertex (h,k) and the distance between the focus with the vertex is p.

The distance of focus and vertex would be -9-0=-9

Then the equation would be:

(x - h)^2 = 4p (y - k)

(x - 0)^2 = 4*-9 (y - 0)

x^2= -36y

y= -1/36 x^2

(x - h)^2 = 4p (y - k)

Where the coordinate of the focus is (h + p, k) , the vertex (h,k) and the distance between the focus with the vertex is p.

The distance of focus and vertex would be -9-0=-9

Then the equation would be:

(x - h)^2 = 4p (y - k)

(x - 0)^2 = 4*-9 (y - 0)

x^2= -36y

y= -1/36 x^2